Programmiersprache

JavaScript

Schwierigkeit

Mittel

Filter active records and return their names.

const users = [
  { name: "Ari", active: true },
  { name: "Bea", active: false },
  { name: "Kai", active: true },
];

const names = users
  .filter((user) => user.active)
  .map((user) => user.name);